How do I check my answer algebraically? the system of equations was 2y=5x-1, x+y=-1 the answer I got was x=-1/7 and y=-6/7

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Answer 1 · 2018-01-12T02:35:29

Please see below.

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Since these $x$ $x$ and $y$ $y$ values are the solution to the system of equations they should work in either equation. Let's try both:

$2 y = 5 x - 1$ $2y=5x-1$

$2 (- \frac{6}{7}) = 5 (- \frac{1}{7}) - 1$ $2(-6/7)=5(-1/7)-1$

$- \frac{12}{7} = - \frac{5}{7} - 1 = \frac{- 5 - 7}{7} = - \frac{12}{7}$ $-12/7=-5/7-1=(-5-7)/7=-12/7$

Let's try the second equation;

$x + y = - 1$ $x+y=-1$

$- \frac{1}{7} + (- \frac{6}{7}) = - \frac{1}{7} - \frac{6}{7} = \frac{- 1 - 6}{7} = - \frac{7}{7} = - 1$ $-1/7+(-6/7)=-1/7-6/7=(-1-6)/7=-7/7=-1$

They both checked out. Your answers are correct.