How do I find the binomial expansion of (1+12x)^(3/4)?

1 Answer
Feb 21, 2015

Use the general formula

(1+X)^\alpha = \sum_{n=0}^\infty (alpha(alpha-1)(alpha -2) ... (alpha -n +1))/(n!) X^n

(1+X)^\alpha = 1 + alpha X + (alpha (alpha -1))/2 X^2 + (alpha (alpha -1)(alpha-3))/6 X^3 + ...

with alpha = 3/4 and X = 12x.