How do I find the derivative of $f(x)=e^(2x)$ ?

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Answer 1 · 2016-01-21T23:51:36

$f'(x)=2*e^(2x)$

$f(x)=e^g(x)$

You can use the Chain Rule:

$f'(x)=e^g(x)*g'(x)$

$:.f'(x)=e^(2x)*2=2*e^(2x)$

you can also write:

$f(x)=e^(2x)=(e^x)^2$

$f(x)=[g(x)]^n$

$f'(x)=n[g(x)]^(n-1)*g'(x)$

$f'(x)=2(e^x)^1*e^x$

remembering that: $a^n*a^m=a^(n+m)$

$f'(x)=2e^(x+x)=e^(2x)$

How do I find the derivative of f(x)=e^(2x) f(x)=e^(2x)?