How do I find the derivative of k(a)=sin^5acos^4a?
How do I even find f'x for sin^5a and cos^4a? I would use the product rule, but I'm lost on just what the derivatives of the separate parts are.
How do I even find f'x for sin^5a and cos^4a? I would use the product rule, but I'm lost on just what the derivatives of the separate parts are.
1 Answer
Apr 30, 2018
Explanation:
- Let
g(a)=sin^5ag(a)=sin5a
- Let
h(a)=cos^4a
Substitute