How do I find the derivative of $ln (\sqrt{x})$ $ln(sqrt(x))$ ?

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Answer 1 · 2015-12-20T06:02:53

$\frac{1}{2 x}$ $1/(2x)$

According to the chain rule,

$d/dx[ln(u)]=(u')/u$

Therefore,

$d/dxln(x^(1/2))=(d/dx[x^(1/2)])/x^(1/2)=(1/2x^(-1/2))/x^(1/2)=1/(2x^(1/2)x^(1/2)$

$=1/(2x)$

How do I find the derivative of ln(sqrt(x)) ln(√x)ln(sqrt(x)) ?