How do I find the derivative of $lnx/x^2$ ?

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Answer 1 · 2015-12-21T00:49:07

$(1-2lnx)/x^3$

Know the identity: $d/dx[lnx]=1/x$

$d/dx[lnx/x^2]=(x^2d/dx[lnx]-lnxd/dx[x^2])/x^4$

$=(x^2(1/x)-lnx(2x))/x^4$

$=(x-2xlnx)/x^4$

$=(1-2lnx)/x^3$

How do I find the derivative of lnx/x^2lnx/x^2?