How do I find the vertex of the function $-6(x-3)^2 -5$ ?

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Answer 1 · 2016-10-04T20:19:36

vertex $->(x,y)=(3,-5)$

This is what they call the vertex form of a quadratic.

Set as $" "y=-6(x color(red)(-3))^2color(green)(-5)$

From this x-vertex $=(-1)xx color(red)(-3) = +3$
From this y-vertex $=color(green)(-5)$

So vertex $->(x,y)=(3,-5)$

Tony B

How do I find the vertex of the function -6(x-3)^2 -5-6(x-3)^2 -5?