How do I simplify (2sqrt(x)*sqrt(x^3))/sqrt(64x^15)2√x⋅√x3√64x15?

1 Answer
Stacey R.
Jan 29, 2015

(2sqrt(x)*sqrt(x^3))/sqrt(64x^15)2√x⋅√x3√64x15
1. Note: sqrt(x)*sqrt(x^3)√x⋅√x3 = x^2x2

--> (2sqrt(x)*sqrt(x^3))/sqrt(64x^15)2√x⋅√x3√64x15 = (2x^2)/sqrt(64x^15)2x2√64x15

  1. Note: sqrt(64x^15)√64x15 = 8x^7sqrt(x)8x7√x

--> (2x^2)/sqrt(64x^15)2x2√64x15 = (2x^2) / (8x^7sqrt(x))2x28x7√x

  1. Now rationalize the denominator

--> (2x^2) / (8x^7sqrt(x)) * sqrt(x)/sqrt(x)2x28x7√x⋅√x√x = (2x^2sqrt(x)) / (8x^7*x) 2x2√x8x7⋅x = (2x^2sqrt(x)) / (8x^8) 2x2√x8x8 = (sqrt(x)) / (4x^6) √x4x6

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