How do I simplify sec x/tan x ?

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Answer 1 · 2018-02-20T05:06:05

$\frac{sec x}{tan x}$ $sec x/tan x$

$\frac{\frac{1}{cos x}}{\frac{sin x}{cos x}}$ $(1/cosx )/(sinx/cosx)$

$1/cancelcosx xx cancelcosx/sinx$

$1/sinx = cscx$

Answer 2 · 2018-02-20T05:07:26

$csc(x)$

Recall that

$tan(x)=sin(x)/cos(x)$

Rewrite your expression:

$sec(x)/[sin(x)/cos(x)]$

Recall that

$sec(x)=1/cos(x)$

Rewrite again:

$(1/cos(x))/(sin(x)/cos(x)]$

$cos(x)$ cancels out:

$1/sin(x)=csc(x)$