Question

How do I solve `3 tan^2 x - sec^2 x -5 = 0`?

Answer 1

`x=pi/3`

Explanation:

Multiply both sides by `cos^2x`
So we get,
`3sin^2x-1-5cos^2x=2sin^2x-6cos^2x=0`
So,
`2sin^2x=6cos^2x`

`tan^2x=3`
`tanx=sqrt(3)`
`x=pi/3`