How do I use Pascal's triangle to expand the binomial (d-3)^6(d3)6?

1 Answer
Sep 28, 2014

Pascal's Triangle looks like this:

1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
1 6 15 20 15 6 1

Using the above numbers as coefficients,

(d-3)^6(d3)6

=1d^6 (-3)^0+6d^5(-3)^1+15 d^4(-3)^2+20 d^3(-3)^3+15 d^2(-3)^4+6 d^1 (-3)^5+1 d^0(-3)^6=1d6(3)0+6d5(3)1+15d4(3)2+20d3(3)3+15d2(3)4+6d1(3)5+1d0(3)6

=x^6-18x^5+135x^4-540x^3+1215x^2-1458x+729=x618x5+135x4540x3+1215x21458x+729