How do solve #ln (2/x) = 1.1#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Alan P. Oct 25, 2015 #x ~= 0.665742# Explanation: #ln(2/x)=1.1# #color(white)("XXXX")#means #e^(1.1) = 2/x# Using a calculator #color(white)("XXXX") e^1.1 ~= 3.004166# #3.004166x~= 2 #x ~= 0.665742# (again, I used a calculator) Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1240 views around the world You can reuse this answer Creative Commons License