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How do solve the following linear system?: $2 x = 4 y, 3 x + 2 y - 3 = 0$ $2x = 4y, 3x+ 2y - 3 = 0$ ?

1 Answer

Aug 9, 2018

$x = \frac{3}{4}$ $x=3/4$ and $y = \frac{3}{8}$ $y=3/8$

Explanation:

From first equation, $x = 2 y$ $x=2y$ .

Hence,

$3 \cdot 2 y + 2 y - 3 = 0$ $3*2y+2y-3=0$

$8 y = 3$ $8y=3$ , so $y = \frac{3}{8}$ $y=3/8$

Thus,

$x = 2 \cdot \frac{3}{8} = \frac{3}{4}$ $x=2*3/8=3/4$

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