How do solve the following linear system?: $\frac{x}{2} - y = - 1, 19 x - 2 y = - 16$ $x/2 - y = -1 , 19x-2y=-16$ ?

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How do solve the following linear system?: $\frac{x}{2} - y = - 1, 19 x - 2 y = - 16$ $x/2 - y = -1 , 19x-2y=-16$ ?

1 Answer

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Answer 1 · 2016-03-12T17:48:22

$x = - \frac{7}{9}, y = \frac{11}{18}$ $x=-7/9, y=11/18$

Explanation:

Multiply the first equation by -2
$- x + 2 y = 2$ $-x+2y=2$
$19 x - 2 y = - 16$ $19x-2y=-16$

$18 x = - 14 \Rightarrow x = - \frac{7}{9}$ $18x=-14=>x=-7/9$
$\frac{x}{2} - y = - 1$ $x/2-y=-1$
$y = \frac{x}{2} + 1$ $y=x/2+1$
$y = - \frac{7}{18} + 1 \Rightarrow y = \frac{11}{18}$ $y=-7/18+1=>y=11/18$

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How do solve the following linear system?: $\frac{x}{2} - y = - 1, 19 x - 2 y = - 16$ $x/2 - y = -1 , 19x-2y=-16$ ?

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How do solve the following linear system?: x/2 - y = -1 , 19x-2y=-16 x2−y=−1,19x−2y=−16 x/2 - y = -1 , 19x-2y=-16 ?

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How do solve the following linear system?: $\frac{x}{2} - y = - 1, 19 x - 2 y = - 16$ $x/2 - y = -1 , 19x-2y=-16$ ?