How do you $\frac{7^{5}}{7^{2}}$ $(7^5)/(7^2)$ ?

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Answer 1 · 2015-07-13T01:47:09

Use the rule of division of powers:

$\frac{x^{a}}{x^{b}} = x^{a - b}$ $x^a/x^b=x^(a-b)$

Or in this case: $= 7^{5 - 2} = 7^{3}$ $=7^(5-2)=7^3$

It's easy to see why this works:

$7^5/7^2=(7*7*7*cancel7*cancel7)/(cancel7*cancel7)$

How do you (7^5)/(7^2)7572(7^5)/(7^2)?