How do you combine #3/(x-3) - 1/x #?

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Answer 1 · 2016-01-02T01:46:44

Place on a common denominator for an answer of #(2x + 3)/(x^2 - 3x)#

#3/(x - 3)-1/x#

The common denominator of these fractions is #x(x-3)=x^2-3x#.

#=3/(x-3)(x/x)-1/x((x-3)/(x-3))#

#=(3x)/(x^2 - 3x)-(x - 3)/(x^2 - 3x)#

#=(3x-(x-3))/(x^2-3x)#

Don't forget to distribute the negative.

#=(2x + 3)/(x^2 - 3x)#