Question

How do you combine `x/(x^2-9) - x/(x^2+6x+9)`?

Answer 1

Write the denominators in the factor form `x/((x-3)(x+3)) - x/(x+3)^2`

= `x/(x+3) [1/(x-3) - 1/(x+3)]`

=`(6x)/((x-3)(x+3)^2)`