How do you compute the derivative of $y = ({sin}^{- 1}) x$ $y=(sin^-1)x$ and x=3/5?

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Answer 1 · 2015-10-16T20:20:56

$2$ $2$

$\frac{d}{d x} {sin}^{- 1} x = \frac{1}{\sqrt{1 - x^{2}}}$ $d/dxsin^(-1)x=1/(sqrt(1-x^2))$

$thereforedy/dx|_(x=3/5)=1/(sqrt(1-(3/5)^2))=2$

How do you compute the derivative of y=(sin^-1)xy=(sin−1)xy=(sin^-1)x and x=3/5?