Question

How do you compute the value of `int sint dt` of `[0, pi]`?

Answer 1

`2`

Explanation:

`int_0^(pi)sintdt`

`=[-cost]_0^(pi)`

`=(-cospi)-(-cos0)`

`=1+1`

`=2`

Answer 2

This is a basic integral, where `intsin(t)dt=-cos(t)+C`.

Evaluating the integral on the interval `[0,pi]`:

`-cos(pi)-(-cos(0))`

`=1-(-1)=2`