How do you compute the value of $int x^5 dx$ of $[1,2]$ ?

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Answer 1 · 2016-11-22T14:23:48

$int_1^2 x^5dx = 21/2$

Using the power rule for integration; $int x^n=x^(n+1)/(n+1) (+c)$

We have:
$int_1^2 x^5dx = [x^6/6]_1^2$

$:. int_1^2 x^5dx = 1/6 [x^6]_1^2$

$:. int_1^2 x^5dx = 1/6 { 2^6 - 1^6 }$
$:. int_1^2 x^5dx = 1/6 { 64- 1 }$
$:. int_1^2 x^5dx = 63/6$
$:. int_1^2 x^5dx = 21/2$

How do you compute the value of int x^5 dxint x^5 dx of [1,2][1,2]?