How do you convert (0, 9) into polar coordinates?

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How do you convert (0, 9) into polar coordinates?

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Answer 1 · 2015-11-07T01:41:21

It turns out that when the argument for the arctangent is undefined, this means that the angle is either $90$ $90$ degrees or $270$ $270$ degrees. Because the y coordinate is positive, this means that the angle theta is $90$ $90$ degrees.

The radius is $r = \sqrt{x^{2} + y^{2}} = \sqrt{0^{2} + 9^{2}} = 9$ $r=sqrt(x^2+y^2)=sqrt(0^2+9^2)=9$

Hence the point $(0, 9)$ $(0,9)$ in polar coordinates is $(9, 90^{o})$ $(9,90^o)$ .

Remember that when you have a point in cartesian cooridnates
$(x, y)$ $(x,y)$ its polar coordinates are

$(\sqrt{x^{2} + y^{2}}, arctan (\frac{y}{x}))$ $(sqrt(x^2+y^2),arctan(y/x))$

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How do you convert (0, 9) into polar coordinates?

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