How do you convert $4x²+y²-8x+4y-9=0$ into standard form?

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Answer 1 · 2016-05-11T03:54:46

Perform a double completion of squares.

$4(x^2 - 2x + 1 - 1) + (y^2 + 4 + 4 - 4) - 9 = 0$

$4(x - 1)^2 - 4 +(y + 2)^2 - 4 - 9 = 0$

$4(x - 1)^2 + (y + 2)^2 = 17$

Hopefully this helps!

How do you convert 4x²+y²-8x+4y-9=04x²+y²-8x+4y-9=0 into standard form?