How do you convert (sqrt(3), 1) into polar forms?

1 Answer
Jan 9, 2016

If (a,b) is a are the coordinates of a point in Cartesian Plane, u is its magnitude and alpha is its angle then (a,b) in Polar Form is written as (u,alpha).
Magnitude of a cartesian coordinates (a,b) is given bysqrt(a^2+b^2) and its angle is given by tan^-1(b/a)

Let r be the magnitude of (sqrt3,1) and theta be its angle.
Magnitude of (sqrt3,1)=sqrt((sqrt3)^2+1^2)=sqrt(3+1)=sqrt4=2=r
Angle of (sqrt3,1)=Tan^-1(1/sqrt3)=pi/6

implies Angle of (sqrt3,1)=pi/6=theta

implies (sqrt3,1)=(r,theta)=(2,pi/6)
implies (sqrt3,1)=(2,pi/6)
Note that the angle is given in radian measure.