Question

How do you convert the cartesian coordinate (18, −6) into polar coordinates?

Answer 1

`18.97 /_-18.43^(o)`

Explanation:

`a^2=18^2+6^2`

`a=sqrt(18^2+6^2)`

`a=sqrt(360)=18.97`

`theta=tg^-1(-6/18)=-18.43^(o)`