How do you determine costheta given tantheta=2/3, pi<theta<(3pi)/2?

1 Answer
Dec 17, 2016

Please see the explanation.

Explanation:

Start with the identity cos^2(theta) + sin^2(theta) = 1

Divide both sides by cos^2(theta):

cos^2(theta)/cos^2(theta) + sin^2(theta)/cos^2(theta) = 1/cos^2(theta)

Use the identity sin(theta)/cos(theta) = tan(theta) and cos^2(theta)/cos^2(theta) = 1:

1 + tan^2(theta) = 1/cos^2(theta)

Solve for cos(theta):

cos^2(theta) = 1/(1 + tan^2(theta))

cos(theta) = +-sqrt(1/(1 + tan^2(theta)))

The domain restriction pi < theta < (3pi)/2 tells us that theta is in the third quadrant (where the cosine function is negative), therefore, we change the +- to - only:

cos(theta) = -sqrt(1/(1 + tan^2(theta)))

Substitute (2/3)^2 for tan^2(theta)

cos(theta) = -sqrt(1/(1 + (2/3)^2))

cos(theta) = -sqrt(1/(1 + 4/9))

cos(theta) = -sqrt(1/(13/9))

cos(theta) = -sqrt(9/13)

cos(theta) = -(3sqrt(13))/13