How do you determine whether (6,-2) is on the line y=1/2x-5y=12x−5?
1 Answer
Mar 10, 2018
Explanation:
"If the point lies on the line then it will satisfy the "If the point lies on the line then it will satisfy the
"equation"equation
"substitute x = 6 into the equation and if the result is "substitute x = 6 into the equation and if the result is
"y= - 2 then "(6,-2)" is on the line"y= - 2 then (6,−2) is on the line
x=6toy=(1/2xx6)-5=3-5=-2x=6→y=(12×6)−5=3−5=−2
rArr(6,-2)" is on the line "y=1/2x-5⇒(6,−2) is on the line y=12x−5