How do you differentiate $2^(2x)$ ?

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Answer 1 · 2016-04-17T07:04:30

$d/dx = 2^(2x) ln 2 *2$

$=2^(2x+1) ln 2$

Use formula $b^u= b^u ln b xx u'$

$d/dx = 2^(2x) ln 2 *2$

$=2*2^(2x) ln2$

$=2^(2x+1) ln 2$

How do you differentiate 2^(2x)2^(2x)?