How do you differentiate $3(x^2-2)^4$ ?

Question

1487 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-09-21T02:11:14

It is $24x*(x^2-2)^3$

We set $f(x)=3*(x^2-2)^4$ hence the derivative is

$(d(f(x)))/dx=12*(x^2-2)^3*(2x)=24x*(x^2-2)^3$

How do you differentiate 3(x^2-2)^43(x^2-2)^4?