How do you differentiate $f (x) = 2 ln (x^{2} + x) - ln (x^{4} + 2 x^{3} + x^{2})$ $f(x)=2ln(x^2+x)-ln(x^4+2x^3+x^2)$ ?

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How do you differentiate $f (x) = 2 ln (x^{2} + x) - ln (x^{4} + 2 x^{3} + x^{2})$ $f(x)=2ln(x^2+x)-ln(x^4+2x^3+x^2)$ ?

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Answer 1 · 2016-02-27T06:59:59

We notice that

$f (x) = 2 ln (x^{2} + x) - ln (x^{4} + 2 x^{3} + x^{2}) \Rightarrow f (x) = {ln (x^{2} + x)}^{2} - {ln (x^{2} + x)}^{2} = 0$ $f(x)=2ln(x^2+x)-ln(x^4+2x^3+x^2)=> f(x)=ln(x^2+x)^2-ln(x^2+x)^2=0$

Hence $\frac{d f}{d x} = 0$ $(df)/dx=0$

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How do you differentiate $f (x) = 2 ln (x^{2} + x) - ln (x^{4} + 2 x^{3} + x^{2})$ $f(x)=2ln(x^2+x)-ln(x^4+2x^3+x^2)$ ?

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How do you differentiate f(x)=2ln(x2+x)−ln(x4+2x3+x2)f(x)=2ln(x^2+x)-ln(x^4+2x^3+x^2)?

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How do you differentiate $f (x) = 2 ln (x^{2} + x) - ln (x^{4} + 2 x^{3} + x^{2})$ $f(x)=2ln(x^2+x)-ln(x^4+2x^3+x^2)$ ?