How do you differentiate $f(x) =arcsec(2x + 1)$ ?

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Answer 1 · 2016-01-30T10:50:10

$f'(x)=2/((2x+1)sqrt((2x+1)^2-1)$

Use the rule : $d/dxsec^(-1)u(x)=1/(usqrt(u^2-1))*(du)/dx$

$therefore d/dxsec^(-1)(2x+1)=2/((2x+1)sqrt((2x+1)^2-1)$

How do you differentiate f(x) =arcsec(2x + 1) f(x) =arcsec(2x + 1) ?