How do you differentiate $f(x) = arctan(1/(1+x^2))$ ?

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Answer 1 · 2016-03-10T20:25:14

$f'(x) = 1/(1+(1/(1+x^2))^2 ) *-(2x)/(1+x^2)^2$

$f'(u)=1/(1+u^2) * u'$
$f'(x) = 1/(1+(1/(1+x^2))^2 ) *-1/(1+x^2)^2 (2x)$
$f'(x) = 1/(1+(1/(1+x^2))^2 ) -(2x)/(1+x^2)^2$

How do you differentiate f(x) = arctan(1/(1+x^2)) f(x) = arctan(1/(1+x^2)) ?