How do you differentiate $f(x)= ln(x^2)$ ?

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Answer 1 · 2015-04-03T01:47:56

You can use the derivative of lnx and the chain rule to get: $f'(x) = 1/x^2*(2x) = 2/x$

Or use $ln(x^2) = 2lnx$ . to get $2*1/x=2/x$

How do you differentiate f(x)= ln(x^2)f(x)= ln(x^2)?