How do you differentiate $f(x)= ln(x^2-x)$ ?

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Answer 1 · 2015-12-24T18:00:22

Using chain rule, which states that $(dy)/(dx)=(dy)/(du)(du)/(dx)$ , let's rename $u=x^2-x$

$(df(x))/(dx)=(1/u)(2x-1)$

$(df(x))/(dx)=(2x-1)/(x^2-x)$

How do you differentiate f(x)= ln(x^2-x)f(x)= ln(x^2-x)?