How do you differentiate $f (x) = ln (x^{3} + 3)$ $f(x)=ln (x^3+3)$ ?

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Answer 1 · 2016-10-31T11:30:20

$f'(x) = (3x^2)/(x^3+3)$

$f(x) = ln(x^3+3)$

To differentiate we use the chain rule:
$d/dxf(g(x)) =f'(g(x))g'(x)$ or, $dy/dx=dy/(du)(du)/dx$

$:. f'(x) = 1/(x^3+3) d/dx(x^3+3)$

$:. f'(x) = 1/(x^3+3)(3x^2)$

$:. f'(x) = (3x^2)/(x^3+3)$

How do you differentiate f(x)=ln (x^3+3)f(x)=ln(x3+3)f(x)=ln (x^3+3)?