How do you differentiate $f (x) = {ln 2}^{x} - 2 ln x$ $f(x)=ln2^x-2lnx$ ?

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Answer 1 · 2015-11-22T16:12:03

$ln 2 - \frac{2}{x}$ $ln2-2/x$

$f'(x)=d/dxstackrel"= x(ln2)"overbrace([ln2^x])-d/dx[2lnx]$

Remember that $ln2$ is just a constant and that $d/dx[lnx]=1/x$ .

$f'(x)=ln2-2(1/x)=color(blue)(ln2-2/x$

How do you differentiate f(x)=ln2^x-2lnx f(x)=ln2x−2lnxf(x)=ln2^x-2lnx ?