How do you differentiate $f(x)=Log_5(x)$ ?

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Answer 1 · 2016-07-24T03:45:28

$(df)/(dx)=0.6213/x$

WE can use here the identity $log_ac=log_abxxlog_bc$

hence $log_5x=log_5exxlog_ex$

= $loge/log5xxlnx$

Hence $f(x)=loge/log5xxlnx$

Now as $loge/log5$ is a constant term,

$(df)/(dx)=loge/log5xx1/x$

= $0.4343/0.69897xx1/x=0.6213/x$

How do you differentiate f(x)=Log_5(x)f(x)=Log_5(x)?