How do you differentiate f(x)=sin(2x^3)? Calculus Basic Differentiation Rules Chain Rule 1 Answer Anjali G Nov 9, 2016 f(x)=sin(2x^3) Chain rule: f'(x)=(cos(2x^3))(6x^2) f'(x)=6x^2cos(2x^3) Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y= 6cos(x^2) ? How do you find the derivative of y=6 cos(x^3+3) ? How do you find the derivative of y=e^(x^2) ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(e^x+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y= (4x-x^2)^10 ? How do you find the derivative of y= (x^2+3x+5)^(1/4) ? How do you find the derivative of y= ((1+x)/(1-x))^3 ? See all questions in Chain Rule Impact of this question 2651 views around the world You can reuse this answer Creative Commons License