How do you differentiate f(x) = Tan^(-1) (x/2)f(x)=tan1(x2)?

1 Answer
Mar 23, 2018

f'(x)=2/(4+x^2)

Explanation:

•color(white)(x)d/dx(tan^-1x)=1/(1+x^2)

"differentiate using the "color(blue)"chain rule"

"Given "f(x)=g(h(x))" then"

f'(x)=g'(h(x))xxh'(x)larrcolor(blue)"chain rule"

f(x)=tan^-1(x/2)

rArrf'(x)=1/(1+(x/2)^2)xxd/dx(1/2x)

color(white)(rArrf'(x))=(1/2)/(1+x^2/4)xx4/4

color(white)(rArrf'(x))=2/(4+x^2)