How do you differentiate $g (a) = sin (arcsin (5 a))$ $g(a)= sin(arcsin(5a))$ ?

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Answer 1 · 2015-05-06T17:20:01

$sin (arcsin (θ)) = θ$ $sin(arcsin(theta)) = theta$

So $g (a) = sin (arcsin (5 a))$ $g(a) = sin(arcsin(5a))$
is simply $g (a) = 5 s$ $g(a)=5s$

$\frac{d g (a)}{d a} = 5$ $(dg(a))/(da) = 5$

How do you differentiate g(a)=sin(arcsin(5a))g(a)= sin(arcsin(5a))?