How do you differentiate: $ln(x^2 +1)$ ?

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Answer 1 · 2015-07-22T18:26:34

I found: $(2x)/(x^2+1)$

I would use the Chain Rule to dela with $ln$ first and multiply times the derivative of the argument to get:
$(dy)/(dx)=1/(x^2+1)*2x=(2x)/(x^2+1)$

How do you differentiate: ln(x^2 +1)ln(x^2 +1)?