How do you differentiate $log 4^(x^2)$ ?

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Answer 1 · 2016-10-18T16:51:56

$d/(dx)log4^(x^2)=1.2042x$

$log4^(x^2)=x^2log4$

Hence $d/(dx)log4^(x^2)=d/(dx)(x^2log4)$

= $log4*d/(dx)x^2$

= $2xlog4$

= $2x xx0.6021$

= $1.2042x$

How do you differentiate log 4^(x^2)log 4^(x^2)?