How do you differentiate $log(8x-1)$ ?

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Answer 1 · 2017-03-31T20:48:11

see below

Use the formula below to find the derivative
$color(red)(d/dx(log_bf(x))=1/(f(x)ln b) * f'(x)$

$y=log (8x-1)$

$color(blue)(y'=1/((8x-1)ln10)*8$

$color(blue)(y'=8/((8x-1)ln10)$

How do you differentiate log(8x-1)log(8x-1)?