How do you differentiate log(sin^2(x))log(sin2(x))?

1 Answer
Feb 10, 2017

2cot(x)2cot(x)

Explanation:

This answer assumes that log(x)=log_e(x)log(x)=loge(x), the natural logarithm.

First use the rule log(a^b)=blog(a)log(ab)=blog(a):

y=log(sin^2(x))=2log(sin(x))y=log(sin2(x))=2log(sin(x))

From here, we need to know that d/dxlog(x)=1/xddxlog(x)=1x. Through the chain rule, d/dxlog(f(x))=1/f(x)*f'(x).

Then:

dy/dx=2(1/sin(x))(d/dxsin(x))=2/sin(x)(cos(x))=2cot(x)