Question

How do you differentiate `r(x)=e^(6x^2-8x)+1/x`?

Answer 1

`r'(x)=e^(6x^2-8x)*(12x-8)-1/x^2`

Explanation:

By the chain rule and the sum rule we get

`r'(x)=e^(6x^2-8x)(12x-8)-1/x^2`