How do you differentiate $sin^4(x)$ ?

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Answer 1 · 2016-11-12T14:15:57

$dy/dx= 4sin^3xcosx$

Let $y= u^4$ and $u = sinx$ .

$y' = 4u^3$ and $u' = cosx$

$dy/dx= 4u^3 xx cosx = 4(sinx)^3cosx = 4sin^3xcosx$

Hopefully this helps!

How do you differentiate sin^4(x)sin^4(x)?