How do you differentiate #siny+x^2+4y=cosx#?
1 Answer
Nov 4, 2016
Explanation:
differentiate
#color(blue)"implicitly with respect to x"#
#rArrcosy.dy/dx+2x+4.dy/dx=-sinx#
#rArrdy/dx(cosy+4)=-sinx-2x#
#rArrdy/dx=-(sinx+2x)/(cosy+4)#
