Question

How do you differentiate `tan(2pix+pi/2)`?

Answer 1

`2pisec^2(2pix+pi/2)`

Explanation:

`"differentiate using the "color(blue)"chain rule"`

`"given "y=f(g(x))" then"`

`dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"`

`"here "y=tan(2pix+pi/2)`

`rArrdy/dx=sec^2(2pix+pi/2)xxd/dx(2pix+pi/2)`

`color(white)(rArrdy/dx)=2pisec^2(2pix+pi/2)`