Question

How do you differentiate `tan (3πx²)`?

Answer 1

`6pixsec^2(3pix^2)`

Explanation:

`"differentiate using the "color(blue)"chain rule"`

`"Given "y=f(g(x))" then"`

`dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"`

`rArrd/dx(tan(3pix^2))`

`=sec^2(3pix^2)xxd/dx(3pix^2)`

`=6pixsec^2(3pix^2)`