How do you differentiate $tan(cos^3(x))$ ?

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Answer 1 · 2015-05-18T02:29:23

Use the Chain Rule: $d/dx(tan(cos^3(x)))=sec^2(cos^3(x))\cdot d/dx(cos^3(x))$

$=sec^2(cos^3(x))\cdot 3cos^2(x)\cdot (-sin(x))$

$=-3sin(x)cos^2(x)sec^2(cos^3(x))$

How do you differentiate tan(cos^3(x))tan(cos^3(x))?