How do you differentiate tan(sqrt(2x+5))? Calculus Basic Differentiation Rules Chain Rule 1 Answer ali ergin Jul 11, 2016 d y=(1+tan^2(sqrt(2x+5)))/(sqrt(2x+5)) * d x Explanation: y=tan sqrt(2x+5) "let's use the chain rule" d y=(1+tan^2sqrt(2x+5))* cancel(2)/ (cancel(2)*sqrt((2x+5))) d x d y=(1+tan^2(sqrt(2x+5)))/(sqrt(2x+5)) * d x Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of y= 6cos(x^2) ? How do you find the derivative of y=6 cos(x^3+3) ? How do you find the derivative of y=e^(x^2) ? How do you find the derivative of y=ln(sin(x)) ? How do you find the derivative of y=ln(e^x+3) ? How do you find the derivative of y=tan(5x) ? How do you find the derivative of y= (4x-x^2)^10 ? How do you find the derivative of y= (x^2+3x+5)^(1/4) ? How do you find the derivative of y= ((1+x)/(1-x))^3 ? See all questions in Chain Rule Impact of this question 1551 views around the world You can reuse this answer Creative Commons License